0
Views
0
Downloads
0
Favorites
trend_v3_v1
//+------------------------------------------------------------------+
//| trend_v3.mq4 |
//| Copyright © 2008, MetaQuotes Software Corp. |
//| http://www.metaquotes.net |
//+------------------------------------------------------------------+
#property copyright "Copyright © 2008, MetaQuotes Software Corp."
#property link "http://www.metaquotes.net"
#property indicator_chart_window
#property indicator_buffers 1
#property indicator_color1 Blue
extern int period =20;
double A[];
//+------------------------------------------------------------------+
//| Custom indicator initialization function |
//+------------------------------------------------------------------+
int init()
{
//---- indicators
SetIndexBuffer(0,A);
SetIndexDrawBegin(0,0);
//----
return(0);
}
//+------------------------------------------------------------------+
//| Custom indicator deinitialization function |
//+------------------------------------------------------------------+
int deinit()
{
//----
//----
return(0);
}
//+------------------------------------------------------------------+
//| Custom indicator iteration function |
//+------------------------------------------------------------------+
int start()
{
int counted_bars=IndicatorCounted();
int i, j, k, q, limit;
double X[2][2], Y[2], B[2], x[2][2000], y[2000], a;
limit=Bars-counted_bars;
for(q=0; q<limit; q++)
{
ArrayInitialize(X,0);
ArrayInitialize(Y,0);
ArrayInitialize(B,0);
ArrayInitialize(x,0);
ArrayInitialize(y,0);
//===========================================
for (i=0; i<=period; i++) {
x[0][i]=1;
x[1][i]=i+q;
y[i]= Close[i+q];
}
//===========================================
for (k=1; k<=period; k++) {
for (j=0; j<=1; j++) {
for (i=0; i<=1; i++) {
X[i][j]=x[j][k]*x[i][k]+X[i][j];
}
Y[j]=y[k]*x[j][k]+Y[j];
}}
//===========================================
k=0;
j=1;
a=X[k][j]/X[k][k];
for (i=0; i<=3; i++){
X[i][j]=X[i][j]-X[i][k]*a;
}
Y[j]=Y[j]-Y[k]*a;
//==========================================
for (k=2; k>=1; k--){
a=0;
for (i=1; i>=k; i--){
a=X[i][k-1]*B[i]+a;
}
B[k-1]=(Y[k-1]-a)/X[k-1][k-1];
}
//=========================================
A[q]=B[0]+B[1]*q;
}
//}
//=========================================
return(0);
}
//+------------------------------------------------------------------+
Comments
Markdown Formatting Guide
# H1
## H2
### H3
**bold text**
*italicized text*
[title](https://www.example.com)

`code`
```
code block
```
> blockquote
- Item 1
- Item 2
1. First item
2. Second item
---